625^-3/4 i know this equals 1/125
for (-32)^3/5 this equals -8 right? I was wondering if someone could explain to me what happens to the 1 and why it is not needed in the answer, but compared to the top one it is needed.
first, yes (-32)^(3/5) = -8
the difference between the two is the negative sign in the exponent.
if you ignore the negative sign at first, you get 125^(-1)...
In other words 625^( 3/4) is 125.
Any number to a -1 power will be equal to one divided by the number. Its a standard exponent property.
The first question, the exponent is negative, according to the exponent rule you have to put it under 1 as a fraction.
Second question, the exponent is positive therefore no fraction is needed.
we know that 10^-2= 10^2 so similarly:
625^-3/4 = 1/ (625^3/4)
obviously 5^4=625 thus
1/(625^3/4) = 1/(5^4^(3/4))
we know 2^5^3= 2^(5*3) = 2^15, similarly
1/(5^4^(3/4) = 1/5^(4*3/4) = 1/5^3
5^3 = 125 therefore
1/5^3 = 1/125
proved
cheers
Thursday, July 22, 2010
CALCULUS- sketch a graph of ONE function that satisfies all of the given conditions?
so my teacher gave us the following problem.. and I don
What is the remainder when 9^6 - 11 divided by 8?
plz b fast.......i stuck up at this question....
9 = 1 (mod 8)
right? Well, then:
9^6 = 9 * 9 * 9 * 9 * 9 * 9 = 1 * 1 * 1 * 1 * 1 * 1 = 1 (mod 8)
So:
9^6 - 11 = 1 - 3 = 6 (mod 8)
(9^6-11) / 8
=(531,441-11) / 8
=531,430 / 8
=66428.75
=
9 = 1 (mod 8)
right? Well, then:
9^6 = 9 * 9 * 9 * 9 * 9 * 9 = 1 * 1 * 1 * 1 * 1 * 1 = 1 (mod 8)
So:
9^6 - 11 = 1 - 3 = 6 (mod 8)
(9^6-11) / 8
=(531,441-11) / 8
=531,430 / 8
=66428.75
=
I just took 250 mg of Tylonol Simply Sleep, am I okay?
How much is deadly?
Well, lets find out shall we?
Given that they are the 25 mg tablets, that means you took 8 more pills than you should have. That
Well, lets find out shall we?
Given that they are the 25 mg tablets, that means you took 8 more pills than you should have. That
Statistics help whats the difference between a t distribution and a z score?
Is it true you only use a t distribution when n is less than 30
Yes, but under some certain circumstances. We can use a t distribution when we know the distribution of the variable is normal, so we use t distribution (this is a condition isn
Yes, but under some certain circumstances. We can use a t distribution when we know the distribution of the variable is normal, so we use t distribution (this is a condition isn
Why doesn
So according to vertical motion, you add the accelaration to the initial velocity forever. Therefore, if the initial velocity is 6 and accelaration is -1, it should be:
6, 5, 4, 3, 2, 1, 0 (and that would make a total of 21) every second
but when I use the formula, d = -u^2/2a I get 18 instead? Why is this happening?
From 0 to 1 sec, the average velocity is (6 5)/2 = 5.5
The second second, the average is 4.5.
Then 3.5, 2.5, 1.5, .5
Add them up and you get 18.
Because acceleration doesn
6, 5, 4, 3, 2, 1, 0 (and that would make a total of 21) every second
but when I use the formula, d = -u^2/2a I get 18 instead? Why is this happening?
From 0 to 1 sec, the average velocity is (6 5)/2 = 5.5
The second second, the average is 4.5.
Then 3.5, 2.5, 1.5, .5
Add them up and you get 18.
Because acceleration doesn
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